A saturated solution of Cu(IO3)2 was prepared in 0.0250 M KIO3. The copper concentration was found to be 0.00072 M. Set up an ICE chart and calculate the equilibrium (IO3-) and the Ksp

0.02644 M = [IO3-]

Ksp = 0.0000005 = 5*10^-7

Explanation:

Step 1: Data given

Asaturated solution of Cu(IO3)2 was prepared in KIO3

Concentration of KIO3 = 0.0250 M

The copper concentration was found to be 0.00072 M

Step 2: Equations

Cu(IO3)2(s) + aq ⇔Cu2+(aq) + 2IO3 -  (aq)

Step 3: The initial concentrations

The initial concentration of KIO3 = 0.0250 M

The initial concentration of Cu2+ is 0 M

Step 4: The changed concentrations

After preparing the Cu2+ in KIO3-; the concentration of Cu2+ will be changed with X

For every 1 Cu2+ we have 2 IO3-

This means if the concentration of Cu2+ is changed by X; the concentration of IO3- is changed by 2X. This gives a total concentration of 0.0250 + 2X for IO3-

Step 4:

Said is that the copper concentration was found to be 0.00072 M

This means the final concentration of Cu2+ is 0.00072 M or also said X = 0.00072

Now we can calculate the final IO3- concentration

0.0250 + 2X  = [IO3-]

0.0250 + 2* 0.00072 = [IO3-]

0.0250 + 0.00144 = [IO3-]

0.02644 M = [IO3-]

Step 5: Calculate Ksp

Cu(IO3)2(s)  ⇔Cu2++ 2IO3 -  

Ksp of Cu(IO3)2 = [Cu+2]*[IO3-]²

Ksp = 0.00072 * 0.02644²

Ksp = 0.0000005 = 5*10^-7

Read also: link

Explanation:

1. The ICE table

2. Concentration of IO₃⁻

At equilibrium, [Cu²⁺] = 0.000 72 mol·L⁻¹, so x = 0.000 72.

The new ICE table becomes

3. Ksp

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .