A vessel contains .672 mol O2, .128 mol CO2, and .200 mol N2. If the total pressure of the vessel is 100 atm, what are the partial pressures of O2, CO2 and N2

See below

Explanation:

n(i)/n(ttl) = p(i)/p(ttl)

p(i) = p(ttl)[n(i)/n(ttl)]

n(ttl) = 0.672 + 0.128 + 0.200 = 1.00

p(O₂) = 100(0.672/1.00) Atm = 67.2 Atm

p(CO₂) =  100(0.0.128/1.00) Atm = 12.8 Atm

p(N₂) =  100(0.0.200/1.00) Atm = 20.0 Atm

the answer is 0.8m.

by: nicholas