Calculate the [OH−]

[H3O+]=3.0×10−9M

Thus the value of [OH⁻] calculated is = 3.3 × 10⁻⁶ M

Explanation:

Given:

Concentration of H₃O⁺ = 3.3 × 10⁻⁹ M

To Find:

Concentration of OH⁻ ion = ?

Solution:

From the value, and the concentration of H⁺ ion, we can find the concentration of hydroxyl ions, as is the product of the concentration of H⁺ and OH⁻ ions. We have the concentration of hydronium ion or H⁺ ion and value, dividing by the H⁺ ion concentration, we will get the concentration of OH⁻ ion as,

= [H₃O⁺] × [OH⁻]

    = 3.0 × 10⁻⁹ × [OH⁻]

Now we have to divide as,

[OH⁻] =   = 3.3 × 10⁻⁶ M

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).