How many liters of O2 gas will be produced at STP from 4 moles of KC1O3

V = 134.5 L

Explanation:

Given data:

Number of moles of KClO₃ = 4 mol

Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃  →  2KCl   + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

                    KClO₃        :           O₂

                        2            :           3

                        4            ;          3/2×4 = 6 mol

Litters of oxygen at STP:

PV = nRT

V = nRT/P

V = 6 mol × 0.0821 atm.L/mol.K × 273 K / 1atm

V = 134.5 L / 1

V = 134.5 L

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