Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the reaction is 2 KClO3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 66.1 g KClO 3 ( s ) .

25.89g of O2 (g)

Explanation:

We begin by finding the molar mass of compounds of interest in the given equation. 2 KClO3 ⟶ 2 KCl + 3 O 2

1  mole of KCLO3 = 39 .10 + 35.5 + (3x16) = 122.55g, 2Moles would be 2 x 122.5 = 245.1g

1 mole Oxygen gas = 32g, 3 moles would be, 3 x 32= 96g

According to the equation;

245.1g of KCLO3 produces 96g of O2 (g)

If 1g of KCLO3  produces  96÷245.1  of O2 (g)  from heating.

66.1g of KCLO3 would produce; 96÷245.1  x 66.1 = 25.89g of O2 (g) from heating.

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explanation:

definition

                    entropy is a measure of the randomness or the extent of disorder of a chemical process.

                      enthalpy is a measure of the heat change of a reaction occurring at a constant pressure.

measurement units:

                        entropy is measured in joule per kelvin (jk⁻¹)   whereas enthalpy is measured in joule per mole (jmol⁻¹)

requirements:

                            entropy has no requirements or limits, and its change is measured by the division between the heat change of the chemical process and the temperature.

                              in contrast, enthalpy can only be related to the heat change of the reaction under standard conditions.