Chemistry, 19.03.2020 21:44 honeybaby675610

Silver sulfate dissolves in water according to the reaction: Ag2SO4(s) ∆ 2 Ag+(aq) + SO42-(aq) Kc = 1.1 * 10-5 at 298 K A 1.5-L solution contains 6.55 g of dissolved silver sulfate. If addi- tional solid silver sulfate is added to the solution, will it dissolve?

Answers: 1

Show answers

Answers

Answer from: mayyyaaa

Silver sulfate dissolves in water according to the reaction: Ag2SO4(s) ∆ 2 Ag+(aq) + SO42-(aq) Kc = 1.1 * 10-5 at 298 K. A 1.5-L solution contains 6.55 g of dissolved silver sulfate. If additional solid silver sulfate is added to the solution, it will not dissolve because the ionic product is equal to the solubility product. When this scenario occurs, the solution in the reaction is saturated and no more solute can be dissolved.

From the given information, the equation for the reaction can be better expressed as:

$\mathbf{Ag_2SO_4 \to 2Ag^+_{(aq)} +SO_4^{2-} _{(aq)}}$

The solubility product is given as 1.1 × 10⁻⁵

Using an ICE table, we have:

$\mathbf{Ag_2SO_4 \to 2Ag^+_{(aq)} +SO_4^{2-} _{(aq)}}$

Initial - 0 0

Change - +2x +x

Equilibrium - 2x x

Now, the solubility product can be expressed as:

$\mathbf{K_{sp}}$ which is = $\mathbf{[Ag^+]^2 [SO_4^{2-}]}$

i.e.

$\mathbf{1.1 \times 10^{-5} = (2x)^2 \times (x)}$

$\mathbf{1.1 \times 10^{-5} = (2x)^3 }$

$\mathbf{ x= \sqrt[3]{\dfrac{1.1\times 10^{-5}}{2} } }$

x = 1.4 × 20⁻² M

Hence, the molar solubility of Ag2SO4(s) is 1.4 × 20⁻² M

We know that;

the concentration of a solution = number of moles/volumeNumber of moles = mass/molar mass

For Ag2SO4(s)

Number of moles = 6.55 g/311.8 g/molNumber of moles = 0.021 molesconcentration of Ag2SO4(s) = 0.021 moles/ 1.5 Lconcentration of Ag2SO4(s) = 0.014 M

Thus, from the given reaction:

$\mathbf{Ag_2SO_4 \to 2Ag^+_{(aq)} +SO_4^{2-} _{(aq)}}$

Since 1 mole of $\mathbf{Ag_2SO_4}$ result in the formation of 2 moles of $\mathbf{ 2Ag^+_{(aq)}}$

Then, 0.014 M = 2(0.014 M) for $\mathbf{ 2Ag^+_{(aq)}}$ = 0.0280 M for $\mathbf{ 2Ag^+_{(aq)}}$

Similarly, 1 mole of $\mathbf{Ag_2SO_4}$ results in the formation of 1 mole of $\mathbf{SO_4^{2-} _{(aq)}}$

∴

ionic product $\mathbf{K_{ip}}$ = (0.0280)²(0.0140)

= 1.1 × 10⁻⁵

Therefore, we can conclude that since $\mathbf{K_{sp}}$ is equal to $\mathbf{K_{ip}}$ , the addition of solid silver sulfate to the solution will not dissolve because the solution in the reaction is saturated and no more solute can be dissolved.

Learn more about solubility product here:

link

Answer from: anastasiakonni1

additional solute will not dissolve.

Explanation:

First we must obtain the number of moles of Ag+ and SO4^2- ions present.

Number of moles of the compound = mass/ molar mass

Molar mass of compound= (2×108) + 32 + 4(16)= 216 + 32 + 64= 312gmol-1

Number of moles of compound= 6.55g/312gmol-1= 0.021moles

Concentration of Ag+ = (2×0.021)/1.5 =0.028M

Concentration of SO4^2- = 0.021/1.5= 0.014M

Qsp = [Ag+]^2[SO42-]= (0.028)^2 ( 0.014)=1.1 x 10^-5 = Ksp

Since Qsp=Ksp, additional solute will not dissolve.

Answer from: Quest

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

Answer from: Quest

C. 1s22s22p63s23p43d104s24p5

Another question on Chemistry

Chemistry, 21.06.2019 20:30

9. write the chemical equation for the following word equations. include symbols for physical states in the equation. a. solid zinc sulfide + oxygen gas -> solid zinc oxide + sulfur dioxide gas b. aqueous hydrochloric acid + aqueous barium hydroxide -> aqueous barium chloride + water

Answers: 1

Answer

Chemistry, 22.06.2019 00:40

1) in saturated limewater, [h+ ]=3.98x10-13 m. a) find [oh]-/ b) what is the ph? / c) is the solution acidic, basic, or neutral? / 2) in butter, [h+ ]=6.0x10-7 m. a) find [oh]-/ b) what is the ph? / c) is the solution acidic, basic, or neutral? / 3) in peaches, [oh]=3.16x10-11 m a) find [h+ ]/ b) what is the ph? / c) is the solution acidic, basic, or neutral? / 4) during the course of the day, human saliva varies between being acidic and basic. if [oh]=3.16x10-8 m, a) find [h+ ]/ b) what is the ph? / c) is the solution acidic, basic, or neutral? /

Answers: 3

Answer

Chemistry, 22.06.2019 04:50

Write the overall equation for the reaction for lithium battery

Answers: 2

Answer

Chemistry, 22.06.2019 08:30

Which part of earth’s surface receives the most direct rays from the sun? a) equator b) ocean c) poles d) mountains

Answers: 2

Answer

You know the right answer?

Silver sulfate dissolves in water according to the reaction: Ag2SO4(s) ∆ 2 Ag+(aq) + SO42-(aq) Kc =...