For the reaction hconh2(g)⇌nh3(g)+co(g), k= 4.84 at 400 k what can be said about this reaction at this temperature? view available hint(s) for the reaction , at 400 what can be said about this reaction at this temperature? the equilibrium lies far to the right. the reaction will proceed very slowly. the reaction contains significant amounts of products and reactants at equilibrium. the equilibrium lies far to the left.

The reaction contains significant amounts of products and reactants at equilibrium.

When a reaction attains equilibrium, the rate of forward reaction becomes equal to the rate of reverse reaction. In that case, the reactants are consumed at the same rate as the products are produced.

Fro the reaction;  HCONH2(g) ⇌ NH3(g) + CO(g), the equilibrium constant of the reaction is 4.84 at 400K. We can infer from the reaction equation that, the reaction contains significant amounts of products and reactants at equilibrium.

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the reaction contains significant amounts of products and reactants at equilibrium.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as

is the constant of a certain reaction at equilibrium for gaseous reactants and products.

For reaction :

The equilibrium lies far to the right when K is much greater than 1.

The equilibrium lies far to the left when K is much lesser  than 1.

Thus as the value of is greater than 1, which means  the reaction contains significant amounts of products and reactants at equilibrium.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)