What is the pressure in a 24.0-LL cylinder filled with 32.7 gg of oxygen gas at a temperature of 319 KK? Express your answer to three significant figures with the appropriate units.

The pressure in that cylinder = 1.12atm

Explanation:

We use general gas law to calculate it. General gas law is gotten by combining Boyle's law, Charles' law and Avogadro's law. Thus

P = nRT/V

Where n = number of moles

R = the gas constant

T is the Temperature, V is the volume and P is the pressure.

Given: T = 319K, V = 24L, R = 0.0821 L.atm/K.mol

The first step is to find n using

n = mass of O2/molar mass of O2

=32.7/32

=1.0219

Now, using P =nRT/V

P = 1.0219 ×0.0821×319÷24

Therefore P = 1.12atm

law of conservation of matter

fdvwsa gfwsargebgeebbfwfwffw gwf   vgwgw gw f gwgw fgw v v dsv dwfff