As a research scientist, you measure the amount of ATP and NADPH consumed by the Calvin cycle in 1 hour. You find 30,000 molecules of ATP consumed, but only 20,000 molecules of NADPH. Where did the extra ATP molecules come from?

The question is incomplete as it does not have the options which are:

A) photosystem II

B) photosystem I

C) cyclic electron flow

D) linear electron flow

E) chlorophyll

Cyclic electron flow

Explanation:

The plants produce ATP molecule by the process of a light-dependent phase of photosynthesis which produces ATP and NADPH molecules.

The ATP and NADPH are produced by the non-cyclic flow of electrons called Z-scheme but when the plant needs extra ATP molecules, they produce more ATP by the cyclic electron flow.

The cyclic electron flow begins when the P₇₀₀ activates electron which then transferred to ferredoxin and then to cyt b₆f and then to plastocyanin. This is repeated and produce ATP molecules escaping the production of NADPH.

Thus, Cyclic electron flow is correct.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied