How many grams of NaCl should be obtained to make 150 mL of 4.5 M solution

39,5 grams should be obtained of NaCl

Explanation:

We calculate the weight of 1 mol of NaCl:

Weight 1 mol NaCl= Weight Na + Weight Cl= 23g + 35,5g=58,5 g/mol

4,5M--> 4,5 moles NaCl in 1000ml (1L) of solution

1000ml4,5 moles NaCl

150 mlx=(150 mlx4,5 moles NaCl)/1000ml=0,675 moles NaCl

1 mol NaCl58,5 grams

0,675molesNaCl---x= (0,675molesNaClx58,5 grams)/1 mol NaCl

x= 39,4879 grams