65ml a 6M solution of HCl are needed to neutralize 82ml of NaOH of an unknown molarity.
a. Write out the reaction that takes place when HCl and NaOH are reacted.

b. Identify the molarity of the NaOH

A. HCl + NaOH —> NaCl + H2O

B. 4.76M

Explanation:

The equation for the reaction is given below:

HCl + NaOH —> NaCl + H2O

From the equation

nA (mole of the acid) = 1

nB (mole of the base) = 1

The following data were obtained from the question:

Ma = 6M

Va = 65mL

Mb =?

Vb = 82mL

Using MaVa/MbVb = nA/nB, the molarity of the base can be obtained as follows:

MaVa/MbVb = nA/nB

6 x 65/ Mb x 82 = 1

Cross multiply to express in linear form.

Mb x 82 = 6 x 65

Divide both side by 82

Mb = (6 x 65) /82

Mb = 4.76M

The molarity of NaOH is 4.76M

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