How many liters of hydrogen gas will be produced at 280.0 K and 96.0 kPa if 40.0 grams of sodium react with excess hydrochloric acid? Write the balanced equation first.

0.0017 litres of H2 will be formed  if 40.0 grams of sodium react with excess hydrochloric acid.

The balanced equation for the reaction:

2Na +2 HCl ⇒  H2 +2 NaCl

Explanation:

the balanced equation for the reaction:

2Na +2 HCl ⇒  H2 +2 NaCl

data given:

Temperature of the reaction = 280 k

pressure of the reaction = 96 kPa

atomic mass of H2 = 2.01 grams/mole

mass of sodium Na = 40 grams

atomic mass of sodium = 22.98 grams/mole

number of moles =

Number of moles =

                              = 1.7 moles of Na will react.

from, the equation 2 moles of Na reacts to form 1 mole of H2

1.7 moles of Na reacts to form x mole of H2

=

x = 0.85 moles of H2 will be formed.

mass of H2 will be calculated by multiplying number of moles with atomic mass of H2

0.85  x 2.01

= 1.708 grams of H2 will be formed.

To convert grams into litre the value in litres is divided by 1000

as 1kg =1000 grams is equal to 1L = 1000 grams

so 0.0017 litres of H2 will be formed.

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