Specific heat of water is 4.18 J/g°C. How many Joules are needed to warm 10 grams of water from 10 to 25 degrees Celsius?

627 J of heat energy is required to warm 10 g of water.

Explanation:

The heat energy required for doing some work is represented as Q. This heat energy will be directly proportional to the product of change in temperature with mass of the object. So the specific heat of the object will act as the proportionality constant.

Thus, it is represented with the symbols Q for hear energy, m for mass of the object, ΔT for the change in temperature and c for specific heat of that object.

Q=mcΔT

As the mass is given as 10g, c is given as 4.18 J/g°C and the change in temperature is ΔT = 25°C-10°C=15°C

So,

Q = 10×4.18×15=627 J

Thus, 627 J of heat energy is required to warm 10 g of water.

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