How many grams of Chlorine are there in 1000 g of Iron(III) chloride?

The amount of chlorine present in iron (iii) chloride is 656.59 g

Explanation:

Given amount of  iron (iii) chloride = 1000 g

Molar mass of Iron (iii) chloride = 162.2 g/mol

Number of moles of Iron (iii) chloride =

Number of moles of chlorine present = (3 6.16 ) mole = 18.49 mole

Atomic mass of chlorine = 35.5 g/mol

Amount of chlorine present = 18.49 mole 35.5 g/mol = 656.59 g

Amount of chlorine present = 656.59 g

they begin to vibrate harder causing the material that was solid to turn into a liquid i.e gallium or ice

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml