A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: Cu2 (aq)+Zn () Cu (s)+Zn2(aq) Suppose the cell is prepared with 0.788 MCu2 in one half-cell and 7.32 M Zn2 in the other Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. 2

Explanation:

We know that,

  = -0.7618 V

   = 0.337 V

According to the given reaction/cell notation,  cathode is ( and anode is ().

Therefore,  

                          = (0.337) - (-0.7618)

                          = 1.0988 V

In the given reaction, number of electrons being transferred in balanced reaction are 2. Hence, n = 2.

Also, we know that

        E =

Putting the given values into the above formula as follows.

       E =  

          =          

          =

           = 1.0704 V

          = 1.07 V (approx)

Thus, we can conclude that the cell voltage under these conditions is 1.07 V.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.