A solution contains 1 LaTeX: \times\:×10−4 M OH– ions. Calculate the solution pH value, and determine if the solution is acidic, basic, or neutral. Helpful math formulas: LaTeX: pH=-\log\left[H_3O^+\right]p H = − log ⁡ [ H 3 O + ] LaTeX: pOH=-\log\left[OH^-\right]p O H = − log ⁡ [ O H − ] LaTeX: pH+pOH=14.00p H + p O H = 14.00 LaTeX: \left[H_3O^+\right]\left[OH^-\right ]=1.0\times10^{-14}1) The pH of the solution is .Enter your answer with 2 significant figures.

2) The solution is .Enter acidic, basic, or neutral.

pH = 10

The solution is basic.

Explanation:

A solution contains 1 × 10⁻⁴ M OH⁻ ions. First, we will calculate the pOH.

pOH = -log [OH⁻]

pOH = -log 1 × 10⁻⁴

pOH = 4

We can find the pH of the solution using the following expression.

pH + pOH = 14.00

pH = 14.00 - pOH = 14.00 - 4 = 10

Since the pH > 7, the solution is basic.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong