A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm Hg

The final temperature at 1050 mmHg is 134.57 or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 = 328 K

Initial pressure = P = 845 mmHg

Assuming final  to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg  

The final temperature is obtained by following relation at constant volume

The final temperature is 407.57 K

supongo que te refieres al paralaje estelar (observable).

si es así, entonces se puede inferir que la estrella está a más de 200 parsecs.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer