Suppose 650.mmol of electrons must be transported from one side of an electrochemical cell to another in 10.0 minutes. Calculate the size of electric current that must flow.

The size of electric current must 104.5 Ampere.

Explanation:

Moles of electrons = 650 mmol =

mmol = 0.001 mol

1 mol = atoms/ions

Number of electrons = N

N =

Charge on an electron =

Total charge on N electrons = Q

Duration of time = T = 10 min = 10 × 60 s

1 minute = 60 seconds

The size of electric current must 104.5 Ampere.