What is the volume, in ml, of 0.183 mol NH3? (at STP).

The volume of ammonia gas is 4096 mL.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.

PV = nRT

So, V = nRT/P

As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol

Then,

V=(0.183*0.082*273)/1

V = 4.096 L = 4096 mL.

Thus, the volume of ammonia gas is 4096 mL.

4099 ml of ammonia at STP is formed.

Explanation:

At STP, standard temperature of 273.15 K and a pressure of 1atm an ideal gas occupies 22.4 litres (molar volume) of volume. Since ammonia is categorized as an ideal gas under the STP it will have:

1 mole of NH3 at STP occupies 22.4litres of volume.

0.183 moles will occupy

22.4 x 0.183

= 4.099 litres of ammonia.

To convert litre into milliliter quantity is multiplied by 1000 as 1 litre equals 1000 ml.

so, 4.099 x 1000

= 4099 ml

The volume occupied by 0.183 moles of ammonia is 4099 ml.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)