Chemistry, 16.03.2020 17:04 125712

Consider the following system at equilibrium:
D(aq)+E(aq)<=>F(aq)
Classify each of the following actions by whether it causes a leftward shift, a rightward shift, or no shift in the direction of the net reaction.
Increase D
Increase E
Increase F
Decrease D
Decrease E
Decrease F
Triple D and reduce E to one third
Triple both E and F

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Answer from: KingJayDevil

Increase D ⇒ rightward shift

Increase E ⇒ rightward shift

Increase F ⇒ leftward shift

Decrease D ⇒ leftward shift

Decrease E ⇒ leftward shift

Decrease F ⇒ rightward shift

Triple D and reduce E to one third ⇒ no shift

Triple both E and F ⇒ no shift

Explanation:

Changes in the concentrations of reactants y products affect to the equilibrium. In this case, D and E are reactants and F is the product.

When a change in the factors affecting equilibrium occur, the system will react in order to counteract the change imposed.

If a increase of reactant occur, the system will tend to produce more products (rightward shift). For example: increase D, increase E. In contraposition, if a decrease of reactant occur, the system will produce more reactants (leftward shift). For example: decrease D, decrease E.If a increase of product occur, the system will tend to produce more reactants (leftward shift). For example: increase F. In contraposition, if a decrease of product occur, the system will produce more products (rightward shift). For example: decrease F.If we change both reactants and products concentration in the same amount, the net change is zero, so there is not shift. For example: Triple D and reduce E to one third (D x 3 and E/3, there is not change in the total amount of reactants) ; Triple both E and F (E x 3 and F x 3, the net change is zero).

Answer from: Quest

Where are the following questions

Answer from: Quest

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.

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