A compound is 40% carbon, 6.7% hydrogen, and 53.3% oxygen. What is the empirical formula?

CH2O

Explanation:

Data obtained from the question include:

C = 40%

H = 6.7%

O = 53.3%

Divide by their molar mass

C = 40/12 = 3.33

H = 6.7/1 = 6.7

O = 53.3/16 = 3.33

Divide by the smallest

C = 3.33/3.33 = 1

H = 6.7/3.33 = 2

O = 3.33/3.33 = 1

The empirical formula is CH2O

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