Calculate the mole fraction of each gas in a mixture of 43.6 g Xe and 36.8 g Kr. show work

Xe = 0.431 mole

Kr = 0.569 mole

Explanation:

We are asked to calculate the mole fraction of each gas

Let's start from, what is mole fraction?

Mole fraction is the ratio of the number of moles of a substance to the total number of moles of all substance present in the mixture

In this question, we are provided with

Xe - 43.6g

Let's find the number of mole

n = m/Mm

n - number of mole

m - number of mass in grams

Mm - number of molar mass

The molar mass of Xe according to the periodic table is 131.293u

m - is given to be 43.6g

n = 43.6g / 131.293g/mol

n = 0.332mole

Secondly,

Kr - 36.8g

The molar mass of Kr is 83.798

m = 36.8

Using the same formula we used above to find mole

n = 36.8g / 83.798g/mol

n = 0.439mole

Let's calculate the total number of mole in the mixture

Total number of mole = 0.332 + 0.439

= 0.771 mole

To find each mole of each gas in the mixture, using this formula

Mole fraction of a gas = mole of gas A / total mole of the mixture

In Xe = 0.332 / 0.771

= 0.431 mole of Xe in the mixture of the gas

For Kr = 0.439 / 0.771

= 0.569 mole of Kr in the total mixture

im not exactly sure but i think its b!

pie chart because it is in percents ( % )