Describe how you would prepare 2.44 kg of an aqueous solution that is 16.3% KOH by mass.
Describe how you would prepare 2.44 of an aqueous solution that is 16.3% by mass.
0.163 kg KOH. Add 0.163 kg KOH to 2.277 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.84 kg water.
0.163 kg KOH. Add 0.163 kg KOH to 2.603 kg water.
2.44 kg solution x 0.163 = 0.40 kg KOH. Add 0.40 kg KOH to 2.04 kg water.
Request Answer

Compare the valence electron configuration of the nobles gas elements seen here. what statement is correct?

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