What is the percent yield of aluminum phosphate if a solution containing 33.4 g of sodium phosphate produced 19.6 g of aluminum phosphate when reacted with excess aluminum chloride in solution

The percent yield of aluminium phosphate in the reaction is 78.78 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of sodium phosphate = 33.4 g

Molar mass of sodium phosphate = 164 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of sodium phosphate and aluminium chloride is:

By Stoichiometry of the reaction:

1 mole of sodium phosphate produces 1 mole of aluminium phosphate

So, 0.204 moles of sodium phosphate will produce = moles of aluminium phosphate

Molar mass of aluminium phosphate = 122 g/mol

Moles of aluminium phosphate = 0.204 moles

Putting values in equation 1, we get:

Experimental yield of aluminium phosphate = 19.6 g

Theoretical yield of aluminium phosphate = 24.88 g

Putting values in above equation, we get:

Hence, the percent yield of aluminium phosphate in the reaction is 78.78 %

dynamic equilibrium is the answer.