A 15.00-mL sample of an NaOH solution of unknown concentration requires 17.88 mL of a 0.1053 M H2SO4 M solution to reach the equivalence point in a titration. What is the concentration of the NaOH solution?

The concentration of the NaOH solution CB = 0.251 M

Explanation:

The balanced equation of reaction is:

H2SO4 + 2NaOH ===> Na2SO4 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)

NB is the number of mole of base = 2 (from the balanced equation of reaction)

CA is the concentration of acid = 0.1053 M

CB is the concentration of base = to be calculated

VA is the volume of acid = 17.88 mL

VB is the volume of base = 15.00mL

Substituting

0.1053×17.88/CB×15 = 1/2

Therefore CB =0.1053×17.88×2/15×1

CB= 0.251 M

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