The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In the first step of the Ostwald process, ammonia is reacted with oxygen gas to produce nitric oxide and water. What is the maximum mass of H 2 O that can be produced by combining 65.8 g of each reactant? 4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

44.5 g of will be produced from the given masses of both reactants.

Explanation:

To calculate the moles :

According to stoichiometry :

5 moles of require 4 moles of

Thus 2.06 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 5 moles of give = 6 moles of

Thus 2.06 moles of give =  of

Mass of

Thus 44.5 g of will be produced from the given masses of both reactants.

thats a little if u want the answer just look it up on google thats what i do haha : )

16

explanation:

the marks go by 4s