Dinitrogentetraoxide partially decomposes according to the following equilibrium: A 1.00-L flask is charged with of . At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is . Question 6 options: 2.2 x 10-4 13 0.22 0.022 0.87

6.4 cm (max) - 25 cm (min)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole