The volume of an ideal gas has decreased from 6.400 L to 20.00 mL at a constant pressure of 3.450 atm. Determine the value of work for this process.

Work = 22.011  j

Explanation:

Given data:

Initial volume = 6.4 L

Final volume = 20.00 mL

Constant pressure = 3.45 atm

Work = ?

Solution:

First of all we will convert the mL into L.

Final volume = 20.00 mL × 1 L/1000 mL

Final volume = 0.02 L

Formula:

Work = Pressure × ΔV

ΔV = initial volume - final volume

ΔV = 6.4 L - 0.02 L

ΔV = 6.38 L

Now we will determine the work done.

Work = Pressure × ΔV

Work = 3.450 atm  × 6.38 L

Work = 22.011 atm.L

Work = 22.011  j

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