"A student started a titration by placing 20.0 mL of 0.24 M NaOH into a flask with 3 drops of phenolphthalein. The student then titrated to the endpoint using 31.0 mL of HCl. Calculate the concentration (molarity) of the HCl that the student used. Show all work for credit."

The answer to your question is 0.15 M

Explanation:

Data

volume of NaOH = 20 ml

[NaOH] = 0.24 M

Volume of HCl = 31 ml

[HCl] = ?

Process

1.- Write the balanced chemical reaction

                    NaOH + HCl  ⇒   NaCl + H₂O

2.- Calculate the moles of NaOH

Molarity = moles / volume (L)

- Solve for volume

moles = Molarity x volume

           = 0.24 x 0.02

           = 0.0048

3.- Use proportions to find the moles of HCl

        1 mol of NaOH 1 mol of HCl

      0.0048 moles of NaOH   x

         x = (0.0048 x 1)/1

         x = 0.0048 moles of HCl

4.- Calculate the concentration of HCl

Molarity = 0.0048 / 0.031

Molarity = 0.15        

the answer is 0.42 is that is an option. this question provides no info