How does oxidation differ from reduction

See the explanation below, please.

Explanation:

In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.

 In oxidation, electrons are lost (positive charge increases). Example:

Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)

On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:

Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)

answer: h+ its less than oh

explanation:

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms