For this reaction: 3 KClO3 to 3 KCL + 4 O2, How many miles of potassium chloride are needed to produce 13 grams of oxygen?

Moles of potassium chloride = 0.3 mol      

Explanation:

Given data:

Number of moles of potassium chloride needed = ?

Mass of oxygen produced = 13 g

Solution:

Chemical equation:

2KClO₃  →  2KCl + 3O₂

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 13 g/ 32 g/mol

Number of moles = 0.41 mol

Now we will compare the moles of oxygen with potassium chloride.

                           O₂            :           KCl

                            3             :             2

                            0.41        :          2/3×0.41 = 0.3

So number of moles of potassium chloride produced would be 0.3 moles.

Mass of potassium chloride:

Mass = number of moles × molar mass

Mass = 0.3 mol × 74.55 g/mol

Mass = 22.4 g                            

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm