Calculate the volume of hydrogen gas that is produced by the reaction of 0.52 grams of solid magnesium with excess hydrochloride acid (HCl). This is a single replacement reaction.

In this given case, he volume of hydrogen gas produced = 0.03969 L

Given:

0.52 grams - solid magnesium

Solution:

moles of Mg

=

= 0.216 x 10⁻³  

Reaction -

Mg + 2HCl -----------------> MgCl2 + H2  

  1mol                                                     1mol  

0.216 x 10⁻³                                     0.216 x 10⁻³ mol  

moles of H2

= 0.216 x 10⁻³  

T  = 273 K

P =1 atm

From idea gas P V = n R T

Placing given and known values in ideal gas

1 x V = 0.216 x 10⁻³ x 0.0821 x 273  

V = 0.048 L  

Thus, the volume of hydrogen gas produced = 0.03969 L

Learn more:

link

0.493L

Explanation:

Let us write a balanced equation for the reaction. This is illustrated below:

Mg + 2HCl —> MgCl2 + H2

Next, let us convert 0.52g of Mg to mole. This is illustrated below:

Molar Mass of Mg = 24g/mol

Mass of Mg = 0.52g

Number of mole of Mg = Mass /Molar Mass = 0.52/24 = 0.022mole

From the equation,

1mole of Mg produced 1mole of H2.

Therefore, 0.022mole of Mg will always produce 0.022mole of H2.

1mole of H2 occupies 22.4L at stp.

Therefore, 0.022mole of H2 will occupy = 0.022 x 22.4 = 0.493L

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

the product of the pressure and volume is also constant