A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 4.10 kg of water at 37.5 degree C. During the reaction 125. kJ of heat flows out of the flask and into the bath.

Calculate the new temperature of the water bath. You can assume the specific heat capacity of water under these conditions is 4.18 J middot g^-1middot K^-1. Round your answer to 3 significant digits.

44.7 degree (3 s.f)

Explanation:

mass of water = 4.10Kg

Initial temperature = 37.5C

Final temperature = x

Heat = 125 kJ = 125000 J

Specific heat capacity = 4180 J/kg°C

These parameters are given by:

H = MCΔT

ΔT = H / MC

ΔT = 125000 / (4.10 * 4180)

ΔT = 7.294

ΔT = T2 - T1

T2 = ΔT + T1

T2 = 7.294 + 37.5

T2 = 44.794 = 44.7 degree (3 s.f)

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