A 186 mL sample of a 0.275 M solution is left on a hot plate overnight. The following morning, the solution is 1.10 M. What volume of solvent has evaporated from the 0.275 M solution?

139.5 mL.

Explanation:

To solve this question we will be making use of dilution law which is given by the equation below;

C1 × V1 = C2 × V2. Where C1 = the initial concentration, V1 = Initial volume, C2 = final concentration, V2 = Initial volume.

So, from the question we are given the following parameters; V1 = 186 mL, C1 = 0.275 M, C2 = 1.10 M and V2 = unknown (??).

Therefore, slotting in the above parameters into the dilution equation we have;

0.275 × 186= 1.10 × V2.

V2 = 0.275 × 186/ 1.10.

V2 = 46.5 mL.

The volume of solvent that has evaporated from the 0.275 M solution = 186 mL - 46.5 mL= 139.5 mL.

139.5 mL.

Explanation:

To solve this question we will be making use of dilution law which is given by the equation below;

C1 × V1 = C2 × V2. Where C1 = the initial concentration, V1 = Initial volume, C2 = final concentration, V2 = Initial volume.

So, from the question we are given the following parameters; V1 = 186 mL, C1 = 0.275 M, C2 = 1.10 M and V2 = unknown (??).

Therefore, slotting in the above parameters into the dilution equation we have;

0.275 × 186= 1.10 × V2.

V2 = 0.275 × 186/ 1.10.

V2 = 46.5 mL.

The volume of solvent that has evaporated from the 0.275 M solution = 186 mL - 46.5 mL= 139.5 mL.

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