Oxygen gas is at a temperature of 40 Celsius when it occupies a volume of 2.3 L. To what temperature should it be raised to occupy a volume of 6.5 L?

The temperature should be 885K.

Explanation:

In this case we use Charles's Law according to which the volume and temperature of a certain amount of gas are related, keeping the pressure constant. We convert the unit of temperature from Celsius to Kelvin: 0 = 273K -> 40 ° C = 40 + 273 = 313K

V1 / T1 = V2 / T2

2,3L/313K= 6,5L/T2

T2=6,5L/(2,3L/313K)=884, 56K

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles