How much mass of iodine would react with 48 grams of magnesium to make magnesium iodide?

Mg + I2 -> MgI2

Mass = 507.6 g

Explanation:

Given data:

Mass of Mg = 48 g

Mass of iodine react = ?

Solution:

Chemical equation:

Mg + I₂ → MgI₂

Now we will determine the number of moles of Mg.

Number of moles = mass/ molar mass

Number of moles = 48 g/ 24 g/mol

Number of moles = 2 mol

Now we will compare the moles of Mg with iodine.

                       Mg           :           I₂

                         1             :            1

                         2            :           2

Mass of iodine:

Mass = number of moles × molar mass

Mass = 2 mol × 253.8 g/mol

Mass = 507.6 g

answer; i believe the correct answer is (solid gold);

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.