Write the balanced molecular equation and net ionic equation for the reaction between hydrofluoric acid and rubidium hydroxide. Include the phases of each species.

The balanced molecular equation and net ionic equation for the reaction between hydrofluoric acid and rubidium hydroxide are as follows;

Balanced molecular equation:

Net ionic equation:

This is the reaction between an acid and a base (Neutralisation reaction)

The molecular equation is therefore;

The Overall ionic equation is given as;

Theres a need to cancel the spectator ions as follows to yield;

Net ionic equation:

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1. Balanced molecular equation:

2. Net ionic equation:

Explanation:

1. Write the word equation

This is the reaction of an acid and a base producing salt plus water.

2. Balanced molecular equation

3. Write the ionic compounds in aqueous solution as ions

Overall ionic equation:

4. Cancel the spectator ions

The spectator ions are those that appear in both sides of the overall ionic equation. In this case they are F⁻ (aq) and  Rb⁺ (aq).

Net ionic equation:

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6