A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 49.1 mark. Calculate the density of the iron piece.

7.92 .g . mL^-1

Explanation:

Data provided in the question

Water liters = 45.5 mL

Pace of iron = 28.5 gram

Rise in the water in the cylinder = 49.1 mark

So by considering the above information

As we know that

where,

Mass = 28.5 gram

Volume = 49.1 - 45.5

              = 3.6 mL

So, the density is

= 7.92 .g . mL^-1

Basically we use the density formula by dividing the mass with the volume

what is the question here. i think you messed up.

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.