In an analysis of the following reaction at a certain temperature, Br2(g) + Cl2(g) ⇌ 2BrCl(g)the equilibrium concentrations were found to be [Br2] = 4.5 ×10−3 M, [Cl2] = 2.6 ×10−2 M, and [BrCl] = 1.6 ×10−2 M. Write the equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.

The equilibrium expression is Equilibrium constant =  

Kc or equilibrium constant for this reaction is 0. 55 x

Explanation:

Br2(g) + Cl2(g) ⇌ 2BrCl(g)

Equilibrium constant =  

Kc =   equation 1

      the concentration of diatoms will be divided by 2

1.3 x 10^-2 is concentration of chlorine

0.45 x 10^-2 is concentration of bromine

1.6 ×10−2 is concentration of BrCl2

Putting the values in equation 1 to calculate equilibrium constant.

Kc=    

Kc =  

Kc= 0.55 x 10^2

equilibrium constant for this reaction is 0.55 x

the molar concentration or partial pressure of the gases is taken to find the equilibrium constant.

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.