3. The molar volume of a gas at STP occupies
0 1 kilopascal
O ooc
12 grams
22.4 L

The molar volume of a gas at STP occupies 22.4 L.

Option D

Explanation:

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

By substituting the above values, in the equation,

V = 22.38 L

explanation:

detials on each model with digrams

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