The equivalent formula weight of an unknown weak acid in g/mol will be determined in this experiment. Calculate this value if it took 18.84 mL of 0.242 M NaOH to titrate or neutralize 2.01 g of the unknown weak acid.

440.79g/mol

Explanation:

Formula weight is measured in g/mol. You already know how many grams you have (2.01g), so you need to calculate how many moles of your acid you have. Neutralization means you have the same number of moles of acid as you do base, so if you calculate the number of moles of base you will find the number of moles of acid:

18.84 mL x 1 L/1000 mL x 0.242 mol/L = (18.84 x 0.242) / 1000 =

0.0045592 mol NaOH,

which means you also started with 0.00456moles of your weak acid.

2.01 g of acid / 0.00456mol of acid gives a formula weight of 440.7894736884 g/mol approximately 440.79g/mol

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.