Consider the reaction. 2 Al ( s ) + Fe 2 O 3 ( s ) heat −−→ Al 2 O 3 ( s ) + 2 Fe ( l ) If 17.3 kg Al reacts with an excess of Fe 2 O 3 , how many kilograms of Al 2 O 3 will be produced?

32.7 kilograms of aluminium oxide  will be produced.

Explanation:

Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )

Moles of aluminium =

According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:

of aluminum oxide

Mass of 320.37 moles of aluminum oxides:

320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg

32.7 kilograms of aluminium oxide  will be produced.

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