Aqueous hydrobromic acid HBr reacts with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O . If 0.555g of sodium bromide is produced from the reaction of 2.4g of hydrobromic acid and 0.77g of sodium hydroxide, calculate the percent yield of sodium bromide. Be sure your answer has the correct number of significant digits in it.

28%

Explanation:

We must obtain the balanced reaction equation as this is the basis for all the calculations that follows. From the balanced reaction equation, 1 mole of hydrobromic acid reacts with one mole of sodium hydroxide to yield one mole each of sodium bromide and water.

Using simple proportion, we obtain the mass of sodium bromide produced by sodium hydroxide since it is the limiting reactant. This is now used to calculate the actual yield of sodium bromide and subsequently the percentage yield as shown.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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