Consider this system at equilibrium. A ( aq ) − ⇀ ↽ − B ( aq ) Δ H = + 850 kJ/mol What can be said about Q and K immediately after an increase in temperature?

Q will increase,

R will remain the same.

Explanation:

We can deduce the equilibrium

A(aq)     ⇒   B (aq)

is an endothermic process since  ΔH  is positive, for which

According to LeChatelier´s principle the disturbance of an increase in temperature for the system will favor the reaction that consumes the added heat so as to minimize the change in temperature.

The system initially then produces more B (aq) and Q > K , but the system will relax back, after the added heat is removed, making Q = Keq again.

Therefore inmediately after the increase in temperature Q will be greater than K eliminating the perturbance of the increase in temperature producing more B(aq), but the system will return to equilibrium by making Q = K

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it