Consider the following compounds and suppose that 0.5 M solutions are prepared of each: NaI, KF, (NH4)Br, KF, KCN, KC2H3O2, CsNO3, and KBr. Which will have solutions that are (a) acidic, (b) basic, and (c) neutral

Explanation:

Salts are ionic compound formed when an acid reacts with a base. The reaction is called the neutralization reaction.The H+ from the acid and OH- from base combine to form water. While the cation from the base and anion from acid forms the salt.There are three types of salt:

NaI: neutralization reaction between strong acid,HI and strong base, NaOH results in the formation of a neutral salt,NaI. Hence the resulting solution is neutral.

KF: neutralization reaction between weak acid, HF and strong base KOH, results in the formation of basic salt,KF. Hence the resulting solution is basic.

NH4Br: neutralization reaction between strong acid, HBr and weak base, NH3, gives an acidic salt,NH4Br. Hence, the resulting solution is acidic.

KCN: neutralization reaction between weak acid, HCN and strong base, KOH, gives a basic salt. Hence the resulting solution is basic.

KC2H3O2: neutralization reaction between weak acid, HC2H3O2, and strong base,KOH, gives a basic salt, hence the resulting solution is basic.

CsNO3: neutralization reaction between strong acid and strong base,i.e CsOH + HNO3, gives a neutral salt. Hence the resulting solution is neutral.

KBr: neutralization reaction between strong acid and strong base, i.e. HBr and KOH, gives a neutral salt. Hence the resulting solution is neutral