If 25 g of potassium nitrate hydroxide reacts with 25bg of magneisum nitartae to produce potassium nitrate and magneisum hydroxide. Determine how much potassium nitrate is produced. what is the limiting reactsnt

0.336 moles of KNO₃ are produced

The limiting reactant is Mg(NO₃)₂

Explanation:

We need to define the reaction to complete this question:

Reactants are: KOH and Mg(NO₃)₂

Products are: KNO₃ and Mg(OH)₂

The reaction is:

2KOH  +  Mg(NO₃)₂  →  2KNO₃  +  Mg(OH)₂

We convert the mass of the reactants, to moles:

25 g / 56.1 g/mol = 0.446 moles

25 g / 148.3 g/mol = 0.168 moles

2 moles of hydroxide need 1 mol of nitrate to react

Then, 0.446 moles of KOH must need (0.446 .1) / 2 = 0.223 moles of nitrate

We do not have enough nitrate, so the Mg(NO₃)₂ is the limiting reagent.

Let's work with the equation and the ratio, which is 1:2

1 mol of Mg(NO₃)₂ produces 2 moles of KNO₃

Then, 0.168 moles of Mg(NO₃)₂ will produce (0.168 . 2) / 1 = 0.336 moles of KNO₃ are produced

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.