The first ionization energy, E , of a nitrogen atom is 2.32 aJ. What is the wavelength of light, in nanometers, that is just sufficient to ionize a nitrogen atom? Values for constants can be found in the Chempendix.

Required wavelength of light is 85.6 nm.

Explanation:

E = h×ν =

E = Energy in J

ν = frequency (Hz s-1)

λ = wavelength in m  

Planck constant h = J s

c = speed of light = m s-1  

2.32 aJ = J

E = h×ν  

- "the acute form of diverticulitis can manifest itself with one or more severe attacks of infection and inflammation.

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as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2