Ou are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1105 M NaOH. You add 20.00 mL of HCOOH to the beaker before titrating, and it requires 35.43 mL of NaOH to reach the end point. What is the concentration of the HCOOH solution

The concentration of the HCOOH solution is 0.1958 M

Explanation:

Step 1: Data given

Concentration of HCOOH = 0.20 M

Concentration of NaOH = 0.1105 M

We add 20.00 mL of HCOOH to the beaker before titrating, and it requires 35.43 mL of NaOH to reach the end point

Step 2: The balanced equation

HCOOH + NaOH → HCOONa + H2O

Step 3: Calculate moles of NaOH

Moles of NaOH = molarity * volume

Moles of NaOH = 0.1105M * 0.03543 L = 0.003915moles

Step 4: Calculate moles HCOOH

For 1 mol HCOOH we need 1 mol NaOH to produce 1 mol HCOONa and 1 mol H2O

For 0.003915 moles NaOH  we need 0.003915 moles HCOOH

Step 5: Calculate concentration of HCOOH

Concentration of HCOOH = moles HCOOH / volume

Concentration of HCOOH = 0.003915 moles / 0.020 L

Concentration of HCOOH = 0.1958 M

The concentration of the HCOOH solution is 0.1958 M

it should be all of them because it asks if you included all of those in your answer

explanation: