In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solution of potassium dichromate (K2Cr2O7) according to the following balanced chemical equation: 2K2Cr2O7(aq) + 8H2SO4(aq) + 3CH3OH(aq) → 2Cr2(SO4)3(aq) + 11H2O(l) + 3 HCOOH(aq) + 2K2SO4(aq) What volume of 0.00143 M K2Cr2O7 is required to titrate 1.90 g of CH3OH dissolved in 50.0 mL of solution

27.64 liters

Explanation:

From the balanced equation, 2 moles of K2Cr2O7 requires 3 moles of CH3OH.

Mole of CH3OH = 1.9/32.04 = 0.0593 mole

Mole of K2Cr2O7 that will require 0.0593 mole of CH3OH:

                   2 x 0.0593/3 = 0.0395 mole

mole = molarity x volume

Volume of K2Cr2O7 needed = 0.0395/0.00143

                             = 27.64 Liter

Hence, 27.64 liters of 0.00143 M K2Cr2O7 will be required to titrate 1.90 g of CH3OH dissolved in 50.0 mL of solution

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.