What is the pH of a buffer prepared by adding 0.809 mol of the weak acid HA to 0.406 mol of NaA in 2.00 L of solution? The dissociation constant Ka of HA is 5.66×10−7.

5.94

Explanation:

Given:-

[salt] = 0.406 mol

[acid] = 0.809 mol

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:

So,  

c. 75.7

i think that is the right

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!